The number of solid spheres ,each of diameter 3 cm that could be moulded to form a solid metal cylinder of height 54 cm and diameter 4 cm is?
Step-by-step Solution:
To solve this problem, we use the principle of volume conservation. When an object is moulded into another shape, the total volume of the material remains the same. Therefore, the total volume of all the small spheres must be equal to the volume of the resulting cylinder.
Number of Spheres (N) × Volume of one Sphere = Volume of the Cylinder
Let N be the number of spheres required.
$N \times (\frac{4}{3}\pi (r_s)^3) = \pi (r_c)^2 h$
We can cancel out $\pi$ from both sides:
$N \times (\frac{4}{3} \times (1.5)^3) = (2)^2 \times 54$
$N \times (\frac{4}{3} \times (\frac{3}{2})^3) = 4 \times 54$
$N \times (\frac{4}{3} \times \frac{27}{8}) = 216$
Simplify the fraction:
$N \times (\frac{108}{24}) = 216$
$N \times (\frac{9}{2}) = 216$
$N = 216 \times \frac{2}{9}$
$N = \frac{432}{9}$
$N = 48$
The number of solid spheres that could be moulded is 48.