The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is:
Step-by-step Solution:
The problem asks for the greatest number 'n' that divides 1657 leaving a remainder of 6, and divides 2037 leaving a remainder of 5. This is a problem that can be solved by finding the Highest Common Factor (HCF).
The underlying principle is:
First, we subtract the respective remainders from each number to find the numbers that our required divisor 'n' must divide perfectly.
Now, we need to find the HCF of 1651 and 2032.
We can use the division method to find the HCF:
The last non-zero remainder is the HCF. In this case, the HCF is 127.
The greatest number which satisfies the given conditions is 127.