In a class of 50 students, it was found that 30 students read "Hitavad", 35 students read "Hindustan" and 10 read neither. How many students read both "Hitavad" and "Hindustan" newpapers?
Step-by-step Solution:
We know the following:\[\] - Total number of students = 50\[\] - Students who read "Hitavad" = 30\[\] - Students who read "Hindustan" = 35\[\] - Students who read neither = 10\[\] Step 1: Calculate the number of students who read at least one newspaper \[\] The total number of students who read at least one newspaper is: \[ \text{Students who read at least one newspaper} = 50 - 10 = 40 \] Step 2: Use the formula for the union of two sets \[\] We can use the principle of inclusion and exclusion to find the number of students who read both newspapers. \[\] The formula is: \[ \text{Students who read both newspapers} = (H_1 + H_2) - \text{Students who read at least one newspaper} \] Where: - \( H_1 = 30 \) (students who read "Hitavad")\[\] - \( H_2 = 35 \) (students who read "Hindustan")\[\] - The total number of students who read at least one newspaper is 40. \[\] Substitute the values: \[ \text{Students who read both newspapers} = (30 + 35) - 40 = 65 - 40 = 25 \] Final Answer: The number of students who read both newspapers is 25.