In a class of 50 students, it was found that 30 students read "Hitavad", 35 students read "Hindustan" and 10 read neither. How many students read both "Hitavad" and "Hindustan" newpapers?
We know the following:\[\] - Total number of students = 50\[\] - Students who read "Hitavad" = 30\[\] - Students who read "Hindustan" = 35\[\] - Students who read neither = 10\[\] Step 1: Calculate the number of students who read at least one newspaper \[\] The total number of students who read at least one newspaper is: \[ \text{Students who read at least one newspaper} = 50 - 10 = 40 \] Step 2: Use the formula for the union of two sets \[\] We can use the principle of inclusion and exclusion to find the number of students who read both newspapers. \[\] The formula is: \[ \text{Students who read both newspapers} = (H_1 + H_2) - \text{Students who read at least one newspaper} \] Where: - \( H_1 = 30 \) (students who read "Hitavad")\[\] - \( H_2 = 35 \) (students who read "Hindustan")\[\] - The total number of students who read at least one newspaper is 40. \[\] Substitute the values: \[ \text{Students who read both newspapers} = (30 + 35) - 40 = 65 - 40 = 25 \] Final Answer: The number of students who read both newspapers is 25.
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