Question 30

Mathematics Scalar and Vector Products Hard

<p>If&nbsp;<span class="math-tex">\(\rm \vec{a},\vec{b},\vec{c}\)</span>&nbsp;are three non-coplanar vectors, then</p> <p><span class="math-tex">\(\rm (\vec{a}+\vec{b}+\vec{c}) \cdot[(\vec{a}+\vec{b}) \times( \vec{a}+\vec{c})]=\)</span></p>

(A) 0
(B) <span class="math-tex">\(\rm [\vec{a}\; \vec{b} \;\vec{c}]\)</span>
(C) 2<span class="math-tex">\(\rm [\vec{a}\; \vec{b} \;\vec{c}]\)</span>
(D) -<span class="math-tex">\(\rm [\vec{a}\; \vec{b} \;\vec{c}]\)</span>
View Dynamic Solution & Explanation
Correct Solution: Option D

Step-by-step Solution:

\[ (\vec a + \vec b + \vec c) \cdot \left[ \left( \vec a + \vec b \right) \times \left( \vec a + \vec c \right) \right] \] This can be expanded as: \[ (\vec a + \vec b + \vec c) \cdot \left[ \vec a \times \vec a + \vec a \times \vec c + \vec b \times \vec a + \vec b \times \vec c \right] \] This simplifies to: \[ \vec a \cdot (\vec b \times \vec c) + \vec b \cdot (\vec a \times \vec c) + \vec c \cdot (\vec b \times \vec a) \] And further: \[ \left[ \vec a \, \vec b \, \vec c \right] + \left[ \vec b \, \vec a \, \vec c \right] + \left[ \vec c \, \vec b \, \vec a \right] = - \left[ \vec a \, \vec b \, \vec c \right] \]