Vertices with the position vectors î - 2ĵ + 2k̂, 2î + ĵ - k̂ and 3î - ĵ + 2k̂ form a triangle. This triangle is:
Step-by-step Solution:
Suppose the vertices are \( A \), \( B \), and \( C \), then: \[ \text{AB} = i - 3j - 3k \] \[ \text{BC} = 2i + j \] \[ \text{CA} = i - 2j + 3k \] Here: \[ \text{BC} \cdot \text{AC} = 2 - 2 = 0 \] Hence, the triangle is right-angled.