\( tan x/2 = tan y/3 = tan z/5\) and x + y + z..." - Step-by-step solution, answer key, and detailed explanation on MCA Prep."> \( tan x/2... - Solved | MCA Prep" /> \( tan x/2 = tan y/3 = tan z/5\) and x + y + z..." - Step-by-step solution, answer key, and detailed explanation on MCA Prep." /> \( tan x/2... - Solved | MCA Prep" /> \( tan x/2 = tan y/3 = tan z/5\) and x + y + z..." - Step-by-step solution, answer key, and detailed explanation on MCA Prep." />

Question 39

Mathematics Trigonometric Equations Hard

If&nbsp;<span class="math-tex">\(\rm \frac{\tan x}{2} = \frac{\tan y}{3} = \frac{\tan z}{5}\)</span>&nbsp;and x + y + z =&nbsp;&pi;, then the value of tan<sup>2</sup>&nbsp;x + tan<sup>2</sup>&nbsp;y + tan<sup>2</sup>&nbsp;z is:

(A) <span class="math-tex">\(\dfrac {38}3\)</span>
(B) <span class="math-tex">\(\dfrac {29}3\)</span>
(C) <span class="math-tex">\(\dfrac {11}3\)</span>
(D) None of these
✓ Correct Answer: Option A Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

Let \( \tan x = 2k, \; \tan y = 3k, \; \tan z = 5k \). We know that when \( x + y + z = \pi \), \[ \tan x + \tan y + \tan z = \tan x \tan y \tan z \] \[ \Rightarrow 2k + 3k + 5k = (2k)(3k)(5k) \] \[ \Rightarrow 10k = 30k^3 \] or \[ k^2 = \frac{1}{3} \] Hence: \[ \tan^2 x + \tan^2 y + \tan^2 z = 4k^2 + 9k^2 + 25k^2 \] \[ = 38k^2 = \frac{38}{3} \]

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