Problem Analysis

The goal is to determine Rishabh's final straight-line distance from his starting point (the fixed point) after a sequence of movements. This is a displacement problem that can be solved using geometry.

Step-by-Step Path

1. Rishabh travels 10 Km west from his office.
2. He turns left (to face south) and travels 8 Km south.
3. He turns left again (to face east) and travels 4 Km east.

Calculation of Final Distance

We can calculate the net displacement in the horizontal (east-west) and vertical (north-south) directions to find his final position relative to the start.

• Net Horizontal Displacement: He moved 10 Km west and then 4 Km east. His final horizontal distance from the start is $10 - 4 = 6$ Km west.
• Net Vertical Displacement: He moved 8 Km south. His final vertical distance from the start is 8 Km south.

These two displacements form the legs of a right-angled triangle. The direct distance from the start is the hypotenuse. We use the Pythagorean theorem ($a^2 + b^2 = c^2$) to find it.

Distance² = (6)² + (8)²
Distance² = 36 + 64
Distance² = 100
Distance = √100
Distance = 10 Km

Therefore, Rishabh is 10 Km far from the fixed point.