Rishabh stops after going 10 Km towards west from his office. Then he goes 8 Km turning to his left. After this he goes 4 Km turning to his left. How far is he from the fixed point?
The goal is to determine Rishabh's final straight-line distance from his starting point (the fixed point) after a sequence of movements. This is a displacement problem that can be solved using geometry.
We can calculate the net displacement in the horizontal (east-west) and vertical (north-south) directions to find his final position relative to the start.
These two displacements form the legs of a right-angled triangle. The direct distance from the start is the hypotenuse. We use the Pythagorean theorem ($a^2 + b^2 = c^2$) to find it.
Distance2 = (6)2 + (8)2
Distance2 = 36 + 64
Distance2 = 100
Distance = √100
Distance = 10 Km
Therefore, Rishabh is 10 Km far from the fixed point.
Reinforce your conceptual grasp with related questions from NIMCET 2020:
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