Question 115

Logical Reasoning Order & Ranking Easy

In a class of 50 students, Raghu's rank is twice that of Paul. There are 10 students who have ranked worse than that of Raghu. Paul's rank in the class is:

(A) 5th
(B) 10th
(C) 15th
(D) 20th
View Dynamic Solution & Explanation
Correct Solution: Option D

Step-by-step Solution:

Step-by-Step Rank Calculation

To find Paul's rank, we first need to determine Raghu's rank from the information given and then use the relationship between their ranks.

1. Finding Raghu's Rank

  • There are a total of 50 students in the class.
  • We are told that 10 students have ranked worse than Raghu. This means 10 students are ranked behind him (from rank 41 to 50).
  • The number of students ranked at or better than Raghu is the total number of students minus those ranked worse than him.
  • Number of students at or better than Raghu's rank = 50 - 10 = 40.
  • Therefore, Raghu's rank is 40th.

2. Finding Paul's Rank

  • The problem states that "Raghu's rank is twice that of Paul."
  • Let R be Raghu's rank and P be Paul's rank. The equation is: R = 2 × P.
  • We can now substitute the value we found for Raghu's rank:
  • 40 = 2 × P
  • P = 40 / 2
  • P = 20

Conclusion

Paul's rank in the class is 20th.