The number of common tangents to the circle \(x^2+y^2=4\) and \(x^2+y^2-6x-8y=24\) is
Step-by-step Solution:
Centre and radius of the first circle are (0, 0) and 2. Centre and radius of the second circle are (3, 4) and 5. Both the circle touch internally, hence there will be only one common tangent.