If \(\frac{n!}{2!(n-2)!}\) and \(\frac{n!}{4!(n-4)!}\) are in the ratio 2:1, then the value of n is
The numbers are \({^n}C_2\) and \({^n}C_4\), clearly \(n \geq 4\). From the options, \(n = 5\) gives the correct ratio.
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