The 10th and 50th percentiles of the observation 32, 49, 23, 29, 118 respectively are
We arrange the data in ascending order: \( 23, 29, 32, 49, 118 \quad n = 5 \) observations. To find \( P_{50} \): \[ P_{50} = 50 \frac{(n+1)}{100} = \frac{50}{100} \times 6 = 3^{\text{rd}} \text{ observation} \] Thus, \( P_{50} = 32 \). To find \( P_{10} \): \[ P_{10} = \frac{10}{100} \times 6 = 0.6 = 1^{\text{st}} \text{ observation} \] Thus, \( P_{10} = 23 \).
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