Let a, b, c, d be non zero numbers. If the point of intersection of the line 4ax + 2ay + c = 0 & 5bx + 2by + d=0 lies in the fourth quadrant and is equidistance from the two are then
If it lies in the fourth quadrant, we get (x, –x) \[2ax + c = 0\] \[3bx + d = 0\] \[ \frac {c}{2a} = \frac {d}{3b} \] \[3bc - 2ad = 0\]
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