Question 24

Mathematics Function and Relation Hard

If \(| x - 6|= | x - 4x | -| x^2- 5x +6 |\) , where x is a real variable

(A) \(x=(2,5)\)
(B) \(x=[2,5] \cup [6, \infty)\)
(C) \(R-[2,6]\)
(D) None of these
✓ Correct Answer: Option D Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

\[ |x-6| = |x-4x| - |x^2-5x+6| \] \[ |x-4x| = |-3x| = 3|x| \] \[ x^2-5x+6 = (x-2)(x-3) \] \[ |x-6| = 3|x| - |(x-2)(x-3)| \] \[ |x-6| + |(x-2)(x-3)| = 3|x| \] Critical points are \(0,2,3,6\). For \(x \ge 6\) \[ |x-6| = x-6, \qquad |(x-2)(x-3)| = (x-2)(x-3) \] \[ x-6 + (x-2)(x-3) = 3x \] \[ x-6 + x^2-5x+6 = 3x \] \[ x^2 -4x = 3x \] \[ x^2 -7x = 0 \] \[ x(x-7)=0 \] \[ x=7 \] For \(3 \le x < 6\) \[ |x-6| = 6-x, \qquad |(x-2)(x-3)| = (x-2)(x-3) \] \[ 6-x + (x-2)(x-3) = 3x \] \[ 6-x + x^2-5x+6 = 3x \] \[ x^2 -6x +12 = 3x \] \[ x^2 -9x +12 = 0 \] \[ x = \frac{9 \pm \sqrt{33}}{2} \] \[ x = \frac{9-\sqrt{33}}{2} \] \[ \therefore x = 7,\; \frac{9-\sqrt{33}}{2} \] These values do not match the given options. \[ \boxed{\text{D. None of these}} \]

Practice Similar Function and Relation Questions

Reinforce your conceptual grasp with related questions from NIMCET 2023:

Q5 The graph of function \(f(x)=log e( x 3+ [] x 6+1 )\) is symmetric about:
Solve →
Q12 If f(x) is a polynomial of degree 4, f(n) = n + 1 for n=1,2,3,4 and f(0) =...
Solve →
Q17 If \(n 1\) and \(n 2\) are the number of real valued solutions \(x = | sin...
Solve →
Q18 The negation of \( S ( R S)\) is equivalent to
Solve →
Q23 Let R be reflexive relation on the finite set a having 10 elements and if...
Solve →
Full-Length Test Series

Prepare for NIMCET Under Real Exam Conditions

Take timed full-length mock tests with authentic question distributions, negative marking (+12/-3 in Math), and instant All India Rank calculation.

Start Free Mock Test Series →