Question 83

Computer Awareness Central Processing Unit (CPU) Easy

If a processor clock is rated as 2500 million cycles per second, then its clock period is:

(A) \(2.50\times{10}^{-10}\, \) sec
(B) \(4.00\times{10}^{-10}\, \) sec
(C) \(1.00\times{10}^{-10}\, \) sec
(D) \(5.00\times{10}^{-10}\, \) sec
View Dynamic Solution & Explanation
Correct Solution: Option B

Step-by-step Solution:

We know that frequency is defined as the number of cycles in one second.
Given:
Number of cycles in 1 second = 2500 million
Therefore, $$ \text{Frequency} = 2500\ \text{MHz} $$ We also know that time period (T) is the inverse of frequency and is defined as the time taken for one cycle: $$ T = \frac{1}{F} $$ Substituting the value: $$ T = \frac{1}{2500 \times 10^6} $$ $$ T = 4 \times 10^{-10} \ \text{seconds} $$