Question 28

Mathematics Continuity Medium

Let \[ f(x) = \begin{cases} \frac{\sin x}{x}, & x \neq 0 \\ 0, & x = 0 \end{cases} \] Then which of the following is true:

(A) \(f(x)\) is not continuous at \(x = 0\)
(B) \(f(x)\) is not differentiable at \(x = 0\)
(C) \(f'(x)\) is not continuous at \(x = 0\)
(D) \(f'(x)\) is continuous at \(x = 0\)
✓ Correct Answer: Option A Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

We are given the function: \[ f(x) = \begin{cases} \frac{\sin x}{x}, & x \neq 0, \\ 0, & x = 0. \end{cases} \] Continuity of \(f(x)\) at \(x = 0\) To check continuity at \(x = 0\), we evaluate the left-hand limit, right-hand limit, and the function value \(f(0)\). \[ \lim_{x \to 0} f(x) = \lim_{x \to 0} \frac{\sin x}{x}. \] Using the standard limit result: \[ \lim_{x \to 0} \frac{\sin x}{x} = 1. \] The value of \(f(0)\) is given as 0. Since: \[ \lim_{x \to 0} f(x) \neq f(0), \] \(f(x)\) is not continuous at \(x = 0\).

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