What is the general solution of the equation \(\cot{\theta} + \tan{\theta} = 2\)?
Step-by-step Solution:
Correct Answer: C ($\theta = n\pi + \frac{\pi}{4}$)
To find the general solution of the equation, we can express it entirely in terms of a single trigonometric function, such as $\tan \theta$.
The given equation is:
$$ \cot \theta + \tan \theta = 2 $$
Since $\cot \theta = \frac{1}{\tan \theta}$, we can substitute this into the equation:
$$ \frac{1}{\tan \theta} + \tan \theta = 2 $$
To eliminate the fraction, we multiply the entire equation by $\tan \theta$ (assuming $\tan \theta \neq 0$):
$$ 1 + \tan^2 \theta = 2 \tan \theta $$
Rearrange the terms to form a quadratic equation:
$$ \tan^2 \theta - 2 \tan \theta + 1 = 0 $$
This is a perfect square trinomial, which can be factored as:
$$ (\tan \theta - 1)^2 = 0 $$
Taking the square root of both sides gives:
$$ \tan \theta - 1 = 0 \implies \tan \theta = 1 $$
We need to find the general solution for $\theta$ where $\tan \theta = 1$.
Substituting our principal value, we get the final general solution:
$$ \theta = n\pi + \frac{\pi}{4} $$