Number of three digit numbers that can be formed using 0, 1, 2, 3 and 5 where these digits are allowed to repeat any number of times, is equal to
Step-by-step Solution:
We need the number of three-digit numbers formed from the digits \(\{0,1,2,3,5\}\) with repetition allowed. A three-digit number cannot begin with \(0\). Thus the first (hundreds) digit has \(4\) choices \(\{1,2,3,5\}\), and each of the tens and units digits has \(5\) choices. Therefore the total number is \[ 4\times 5\times 5=100. \] \[ \boxed{100} \]