The value of \({3}^{3-\log _35}\) is
Step-by-step Solution:
\[ \begin{aligned} & \text{We know } a^{\log_a x} = x, \\ & 3^{3 - \log_3 5} = 3^3 \cdot 3^{-\log_3 5} = 3^3 \cdot 3^{\log_3 \left( \frac{1}{5} \right)}, \\ & = 27 \cdot \left( \frac{1}{5} \right) = \frac{27}{5}. \end{aligned} \]