Question 95

Computer Awareness Central Processing Unit (CPU) Easy

If a processor clock is rated as 2500 million cycles per second, then its clock period is:

(A) \(2.50 * 10^{-10} sec\)
(B) \(4.0 * 10^{-10} sec\)
(C) \(1.00 * 10^{-10} sec\)
(D) None of the above
View Dynamic Solution & Explanation
Correct Solution: Option B

Step-by-step Solution:

To calculate the clock period, we use the formula: \[ \text{Clock Period (T)} = \frac{1}{\text{Clock Frequency (f)}} \]
Given:
Clock frequency (\( f \)) = 2500 million cycles per second = \( 2.5 \, \text{GHz} \) = \( 2.5 \times 10^9 \, \text{Hz} \)

Calculation: \[ T = \frac{1}{2.5 \times 10^9} = 0.4 \, \text{nanoseconds (ns)} \]

Final Answer: The clock period is 0.4 nanoseconds (ns).