If (2, 1), (–1, –2), (3, 3) are the midpoints of the sides BC, CA, AB of a triangle ABC, then equation of the line BC is
Let D(2, 1), E(−1, −2), F(3, 3) be the midpoints of BC, CA, AB.
By the midpoint theorem, BC is parallel to EF.
Slope of EF = \(\frac{3 - (-2)}{3 - (-1)} = \frac{5}{4}\)
BC passes through D(2, 1) with slope \(\frac{5}{4}\):
\(y - 1 = \frac{5}{4}(x - 2) \Rightarrow 4y - 4 = 5x - 10 \Rightarrow 5x - 4y - 6 = 0\)
Answer: (B)
Reinforce your conceptual grasp with related questions from MAH MCA CET 2015:
Take timed full-length mock tests with authentic question distributions, negative marking (+12/-3 in Math), and instant All India Rank calculation.
Start Free Mock Test Series →