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Consider the equation (43)<sub>x</sub> = (y3)<sub>8 </sub>where x and y are unknown. The number of possible solution is
\((43)_x = 4x + 3\) and \((y3)_8 = 8y + 3\).
\(4x + 3 = 8y + 3 \Rightarrow x = 2y\).
Conditions:
\(x = 2y \ge 5\) gives \(y \ge 3\). So y = 3, 4, 5, 6, 7 (with x = 6, 8, 10, 12, 14).
Number of solutions = 5.
Answer: (C) 5
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