2 from (1101)2 using first complement" - Step-by-step solution, answer key, and detailed explanation on MCA Prep."> 2 from (1101)2 using first complement" - Step-by-step solution, answer key, and detailed explanation on MCA Prep." /> 2 from (1101)2 using first complement" - Step-by-step solution, answer key, and detailed explanation on MCA Prep." />
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Question 97

Computer Awareness Boolean algebra Easy

Subtract (1010)<sub>2</sub>&nbsp;from (1101)<sub>2</sub>&nbsp;using first complement

(A) (1100)<sub>2</sub>
(B) (0101)<span style="position: relative; line-height: 0; vertical-align: baseline; bottom: -0.25em;font-size:10.5px;">2</span>
(C) (1001)<span style="position: relative; line-height: 0; vertical-align: baseline; bottom: -0.25em;font-size:10.5px;">2</span>
(D) (0011)<span style="position: relative; line-height: 0; vertical-align: baseline; bottom: -0.25em;font-size:10.5px;">2</span>
✓ Correct Answer: Option D Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

To find \(1101 - 1010\) using 1's complement:

  1. 1's complement of 1010 = 0101
  2. Add: 1101 + 0101 = 1 0010
  3. There is an end-around carry, so add it back: 0010 + 1 = 0011

Check: 13 − 10 = 3 = 0011.

Answer: (D) 0011

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