Question 28

Mathematics Function and Relation Easy

Which of the following functions is the inverse of itself?

(A) <span class="math-tex">\(f(x)=\dfrac{(1-x)}{1+x}\)</span>
(B) <span class="math-tex">\(f(x)=3^{\log x}\)</span>
(C) <span class="math-tex">\(f(x)=3^{x(x+1)}\)</span>
(D) None of these
✓ Correct Answer: Option A Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

A function is its own inverse if \(f(f(x)) = x\).

For \(f(x) = \frac{1-x}{1+x}\): \(f(f(x)) = \frac{1 - \frac{1-x}{1+x}}{1 + \frac{1-x}{1+x}} = \frac{(1+x) - (1-x)}{(1+x) + (1-x)} = \frac{2x}{2} = x\)

So it is its own inverse.

Answer: (A)

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