1, a2, a3, ..., a2n - 1, b are in AP, a,..." - Step-by-step solution, answer key, and detailed explanation on MCA Prep."> 1, a2, a3, ..., a2n - 1, b are in AP, a,..." - Step-by-step solution, answer key, and detailed explanation on MCA Prep." /> 1, a2, a3, ..., a2n - 1, b are in AP, a,..." - Step-by-step solution, answer key, and detailed explanation on MCA Prep." />

Question 10

Mathematics Sequence And Series Hard

If a, a<sub>1</sub>, a<sub>2</sub>, a<sub>3</sub>, ..., a<sub>2n - 1</sub>, b are in AP, a, b<sub>1</sub>, b<sub>2</sub>, ... b<sub>2n - 1</sub>, b are in GP and a, c<sub>1</sub>, c<sub>2</sub>, c<sub>3</sub>, ..., c<sub>2n - 1</sub>, b re in HP, where a, b are positive, then the equation a<sub>n</sub>x<sup>2</sup> - b<sub>n</sub>x + c<sub>n</sub> = 0 has its roots

(A) Real and equal
(B) Real and unequal
(C) Imaginary
(D) One real and one imaginary
✓ Correct Answer: Option C Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

\(a_n\), \(b_n\), \(c_n\) are the middle terms of the AP, GP and HP between a and b. So they are the AM, GM and HM of a and b:

\(a_n = A\), \(b_n = G\), \(c_n = H\), with \(G^2 = AH\).

Discriminant = \(b_n^2 - 4a_nc_n = G^2 - 4AH = G^2 - 4G^2 = -3G^2 < 0\)

So the roots are imaginary.

Answer: (C)

Practice Similar Sequence And Series Questions

Reinforce your conceptual grasp with related questions from MAH MCA CET 2019:

Q12 If a, b, c are in GP and log a - log 2b, log 2b - log 3c and log 3c - log...
Solve →
Q14 If x, 2x + 2, 3x + 3 are the first three terms of a geometric progression,...
Solve →
Q41 The sum of infinite terms of a decreasing GP is equal to the greatest...
Solve →
Q50 Number of real solution of the equation sin (ex) =...
Solve →
Q1 For two circles x2 + y2 = 16 and x2...
Solve →
Full-Length Test Series

Prepare for MAH MCA CET Under Real Exam Conditions

Take timed full-length mock tests with authentic question distributions, negative marking (+12/-3 in Math), and instant All India Rank calculation.

Start Free Mock Test Series →