Question 54

Logical Reasoning Data Sufficiency / Interpretation Easy

Cricket clubs in five towns A, B, C, D and E have one team each named P, Q, R, S and T, not necessarily in the same order. The team in A has beaten R, P and S. Q has beaten the teams in E, C and A. Team R is in B and the team in C is not S. Which team is in A?

(A) P
(B) Q
(C) S
(D) T
View Dynamic Solution & Explanation
Correct Solution: Option D

Step-by-step Solution:

Logical Deduction Steps




  1. First, we use the most direct clue: "Team R is in B". This gives us our first certain match: Town B = Team R.


  2. Next, the clue "Q has beaten the teams in E, C, and A" means Q's own town cannot be E, C, or A. Since we already know B is taken by R, the only town left for Q is D. So, Town D = Team Q.


  3. Now, the clue "The team in A has beaten R, P, and S" means the team in A cannot be R, P, or S. We also know it's not Q (which is in D). By elimination from the original list (P, Q, R, S, T), the only team left for town A is T. So, Town A = Team T.


  4. Finally, the remaining towns are C and E, and the remaining teams are P and S. The clue "The team in C is not S" eliminates one possibility. Therefore, Town C must be Team P, which leaves Town E as Team S.




Final Arrangement



Town A = Team T
Town B = Team R
Town C = Team P
Town D = Team Q
Town E = Team S




The team T is in Town A.