\( a = 4 j \) and \( b..." - Step-by-step solution, answer key, and detailed explanation on MCA Prep."> \( a = 4 j... - Solved | MCA Prep" /> \( a = 4 j \) and \( b..." - Step-by-step solution, answer key, and detailed explanation on MCA Prep." /> \( a = 4 j... - Solved | MCA Prep" /> \( a = 4 j \) and \( b..." - Step-by-step solution, answer key, and detailed explanation on MCA Prep." />

Question 50

Mathematics Scalar and Vector Products Hard

If&nbsp;<span class="math-tex">\(\vec{a} = 4\hat{j}\)</span>&nbsp;and&nbsp;<span class="math-tex">\(\vec{b} = 3\hat{j} + 4\hat{k}\)</span>, then the vector form of the component of&nbsp;<span class="math-tex">\(\vec{a}\)</span>&nbsp;along&nbsp;<span class="math-tex">\(\vec{b}\)</span>&nbsp;is

(A) <span class="math-tex">\(\dfrac{12}{10\sqrt{3}}(3\hat{j}+4\hat{k})\)</span>
(B) <span class="math-tex">\(\rm \dfrac {12}{25}(3\vec j + 4 \vec k)\)</span>
(C) <span class="math-tex">\(\dfrac{12}{\sqrt{13}}(3\hat{j}+4\hat{k})\)</span>
(D) <span class="math-tex">\((3\hat{j}+4\hat{k})\)</span>
โœ“ Correct Answer: Option B Verified Solution

๐Ÿ“˜ Step-by-Step Solution & Detailed Explanation:

The vector component of \(\vec{a}\) along \(\vec{b}\) is \(\left(\frac{\vec{a} \cdot \vec{b}}{|\vec{b}|^2}\right)\vec{b}\).

\(\vec{a} \cdot \vec{b} = 4 \times 3 = 12\) and \(|\vec{b}|^2 = 9 + 16 = 25\).

Component = \(\frac{12}{25}(3\hat{j} + 4\hat{k})\)

Answer: (B)

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