\(tan x = -3 4 \) and If <span class="math-tex">\(\tan x = \dfrac{-3}{4}\)</span> and <span class="math-tex">\(\dfrac{3\pi}{2}< x < 2\pi\)</span>, then the value of sin 2x is \begin{aligned}
\sin 2x &= \frac{2 \tan x}{1 + \tan^2 x} \\
&= \frac{2 \times \frac{-3}{4}}{1 + \left(\frac{-3}{4}\right)^2} \\
&= \frac{\frac{-3}{2}}{\frac{16 + 9}{16}} \\
&= \frac{-3}{2} \times \frac{16}{25} = \frac{-24}{25}
\end{aligned}
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