The slope of the function at x = 0.

\(f( x ) = \ * 20 c x 2..." - Step-by-step solution, answer key, and detailed explanation on MCA Prep."> The slope of the function at x = 0.

\(f( x ) = \ * 20 c x 2..." - Step-by-step solution, answer key, and detailed explanation on MCA Prep." /> The slope of the function at x = 0.

\(f( x ) = \ * 20 c x 2..." - Step-by-step solution, answer key, and detailed explanation on MCA Prep." />

Question 38

Mathematics Limit of Functions Hard

<p>The slope of the function at x = 0.</p> <p><span class="math-tex">\(f\left( x \right) = \left\{ {\begin{array}{*{20}{c}} {{x^2}\sin \left( {\frac{1}{x}} \right),}&amp;{x \ne 0}\\ {0,}&amp;{x = 0} \end{array}} \right.\)</span>&nbsp;?</p>

(A) 1
(B) 0
(C) -1
(D) None
✓ Correct Answer: Option B Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

\[ f(x) = \begin{cases} x^2 \sin \left( \frac{1}{x} \right), & x \neq 0 \\ 0, & x = 0 \end{cases} \] \[ m = \frac{dy}{dx} = \lim_{x \to 0} \frac{f(x) - f(0)}{x - 0} \] \[ \lim_{x \to 0} \frac{x^2 \sin \left( \frac{1}{x} \right) - 0}{x} \] \[ \lim_{x \to 0} x \sin \left( \frac{1}{x} \right) \] \[ -1 \leq \sin \left( \frac{1}{x} \right) \leq 1 \] \[ \Rightarrow - x \leq x \sin \left( \frac{1}{x} \right) \leq x \] \[ \Rightarrow \lim_{x \to 0} (-x) \leq \lim_{x \to 0} x \sin \left( \frac{1}{x} \right) \leq \lim_{x \to 0} x \] \[ \Rightarrow 0 \leq \lim_{x \to 0} x^2 \sin \left( \frac{1}{x} \right) \leq 0 \] \[ \therefore \lim_{x \to 0} x^2 \sin \left( \frac{1}{x} \right) = 0 \]

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