Question 33

Mathematics Limit of Functions Hard

\(\lim_{x \to \infty} (\frac{x+7}{x+2})^{x+5}\) equal to

(A) \(e^{5}\)
(B) \(e^{-5}\)
(C) \(e^{2}\)
(D) \(e^{-2}\)
View Dynamic Solution & Explanation
Correct Solution: Option A

Step-by-step Solution:

\[ \mathop {\lim }\limits_{x \to \infty } {\left( {\frac{{x + 7}}{{x + 2}}} \right)^{x + 5}} = \mathop {\lim }\limits_{x \to \infty } {\left( {{{\left( {1 + \frac{5}{{x + 2}}} \right)}^{x + 2}}} \right)^{\frac{{x + 5}}{{x + 2}}}} \] \[ = \mathop {\lim }\limits_{x \to \infty } {\left( {{e^5}} \right)^{\frac{{x + 5}}{{x + 2}}}} = {e^5} \]