A company produces five different products. The sales of these five products (in lakh number of packs) during 2005 and 2010 are shown in the following bar – graph. Question is based on this graph. Sales (in lakh number of packs) of five different products of a company during 2005-2010.The sales of Products A in 2010 was by that percent more than the sales of Product B in 2010? (rounded off to the nearest integer)
From the bar chart, we find the sales figures (in lakh packs) for 2010:
The formula for how much percent A is more than B is ((A - B) / B) * 100.
((48.17 - 37.16) / 37.16) * 100= (11.01 / 37.16) * 100≈ 29.63%Rounding the result to the nearest integer gives us:
30%
Final Answer: Based on the data in the chart, the sales of Product A in 2010 were approximately 30% more than the sales of Product B in 2010.
Reinforce your conceptual grasp with related questions from NIMCET 2021:
Take timed full-length mock tests with authentic question distributions, negative marking (+12/-3 in Math), and instant All India Rank calculation.
Start Free Mock Test Series →