Two friends A and B were standing at the diagonally opposite corners of a rectangular plot whose perimeter is 100m. A first walked x meters along the length of the plot towards East and then y meters towards the South. B walked x meters along the breadth towards North and then y meters towards West. At the end of their walks, A and B were standing at the diagonally opposite corners of a smaller rectangular plot whose perimeter is 40m. How much distance did A walk?
To solve this problem, we can set up algebraic equations based on the perimeters of the two rectangular plots described.
Two friends, A and B, start at diagonally opposite corners and walk to new positions, which become the corners of a smaller rectangle.
The perimeter of the new, smaller plot is 40m.
2 × ((L - x - y) + (B - x - y)) = 40
Dividing by 2, we get:
(L - x - y) + (B - x - y) = 20
Rearranging the terms:
(L + B) - 2(x + y) = 20
We can now substitute the result from the first step (L + B = 50) into our second equation:
50 - 2(x + y) = 20
30 = 2(x + y)
x + y = 15
The total distance A walked is the sum of his horizontal walk (x) and his vertical walk (y).
The total distance A walked is x + y, which is 15 meters.
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