A vessel contains total 95 litre mixture of milk & water in the ratio of 15 : 4 respectively. P litre of mixture taken out from the vessel and 18 litres water added in the remaining mixture, then the new ratio of milk to water becomes 3 : 2, find the value of P?
Step-by-step Solution:
To find the value of P, we first need to determine the initial amounts of milk and water, and then set up an equation based on the changes described.
The vessel contains 95 litres of a mixture with a Milk to Water ratio of 15 : 4.
15 + 4 = 19.95 litres / 19 parts = 5 litres/part.15 parts * 5 = 75 litres.4 parts * 5 = 20 litres.When P litres of the mixture are removed, the milk and water are removed in the same 15:4 ratio. Afterwards, 18 litres of pure water are added.
(15 / 19) * P. The final amount of milk is 75 - (15/19)P.(4 / 19) * P. The final amount of water is (20 - (4/19)P) + 18.The new ratio of Milk to Water is 3 : 2. This gives us the equation:
(75 - 15P/19) / (38 - 4P/19) = 3 / 2 Now, we solve the equation by cross-multiplying:
2 * (75 - 15P/19) = 3 * (38 - 4P/19) 150 - 30P/19 = 114 - 12P/19 Group the terms with P and the constant terms:
150 - 114 = 30P/19 - 12P/19 36 = 18P/19 Isolate P:
P = (36 * 19) / 18 P = 2 * 19 = 38 Final Answer: The value of P is 38 litres.