A coin is thrown 8 number of times. What is the probability of getting a head in an odd number of throw?
Step-by-step Solution:
Total throws = 8 \[\] Odd-numbered throws = \( \{1, 3, 5, 7\} \), count = 4 \[\] Probability (\( P(E) \)) of getting a head in odd-numbered throws: \[ P(E) = \frac{1}{2} \]