Question 54

Logical Reasoning Aptitude Easy

The mean of consecutive positive integers from 2 to \(n\) is:

(A) \(\frac{n + 2}{2}\)
(B) \(\frac{n(n + 1)}{2}\)
(C) \(\frac{n + 1}{2}\)
(D) \(\frac{n - 1}{2}\)
View Dynamic Solution & Explanation
Correct Solution: Option A

Step-by-step Solution:

The mean of consecutive positive integers from 2 to n

The mean of a set of consecutive integers can be found using the formula:
Mean = (First Term + Last Term) / 2


In this problem, the consecutive positive integers are from 2 to n.


  • The first term is 2.
  • The last term is n.

Substituting these values into the formula:
Mean = (2 + n) / 2
Mean = (n + 2) / 2


Answer:

The correct option is (A) (n+2)/2.