Step-by-step Solution:

Quick Solution

To solve this, we need to count the total number of days between the start date and the end date. A simpler way is to count the "odd days" for each month in between. An odd day is any day left over after dividing a month's total days by 7.

1. Count the Odd Days for Each Month

We'll list the months and calculate the odd days from the end of September 1991 up to our target date.

• September 1991: Has 30 days. We start after the 30th, so 0 days remain. -> 0 odd days.
• October 1991: Has 31 days. (31 ÷ 7 = 4 rem 3) -> 3 odd days.
• November 1991: Has 30 days. (30 ÷ 7 = 4 rem 2) -> 2 odd days.
• December 1991: Has 31 days. -> 3 odd days.
• January 1992: Has 31 days. -> 3 odd days.
• February 1992: Has 29 days (because 1992 is a leap year). (29 ÷ 7 = 4 rem 1) -> 1 odd day.
• March 1992: We count up to the 14th. 14 days. (14 ÷ 7 = 2 rem 0) -> 0 odd days.

2. Calculate the Total Odd Days and Final Day

- Now, we sum up all the odd days:
Total Odd Days = 0 + 3 + 2 + 3 + 3 + 1 + 0 = 12 days.

- To find the final shift in the day of the week, we find the remainder of this total when divided by 7:
12 ÷ 7 = 1 with a remainder of 5.

- The required day is 5 days after the starting day (Wednesday).
- Wednesday + 5 days = Monday.

Final Answer: The day on 14th March 1992 was a Monday.