\( a = i + j + k,\; b = i - j + k\) and c = î -..." - Step-by-step solution, answer key, and detailed explanation on MCA Prep."> \( a = i... - Solved | MCA Prep" /> \( a = i + j + k,\; b = i - j + k\) and c = î -..." - Step-by-step solution, answer key, and detailed explanation on MCA Prep." /> \( a = i... - Solved | MCA Prep" /> \( a = i + j + k,\; b = i - j + k\) and c = î -..." - Step-by-step solution, answer key, and detailed explanation on MCA Prep." />

Question 20

Mathematics Scalar and Vector Products Hard

Let&nbsp;<span class="math-tex">\(\rm \vec a =\hat i +\hat j +\hat k,\; \vec b =\hat i -\hat j + \hat k\)</span>&nbsp;and c = î - ĵ - k̂ be three vectors. A vector&nbsp;<span class="math-tex">\(\rm \vec v\)</span>&nbsp;in the plane of&nbsp;<span class="math-tex">\(\rm \vec a\)</span>&nbsp;and&nbsp;<span class="math-tex">\(\rm \vec b\)</span>&nbsp;whose projection on&nbsp;<span class="math-tex">\(\rm \frac {\vec c} {|\vec c|}\)</span>&nbsp;is&nbsp;<span class="math-tex">\(\frac 1 {\sqrt 3},\)</span>&nbsp;is

(A) 3î - ĵ + 3k̂
(B) î - 3ĵ + 3k̂
(C) 5î - 2ĵ + 5k̂
(D) 2î - ĵ + 3k̂
✓ Correct Answer: Option A Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

A vector in the plane of \(\vec{a}\) and \(\vec{b}\) is \(\vec{v} = \vec{a} + \lambda\vec{b} = (1+\lambda)\hat{i} + (1-\lambda)\hat{j} + (1+\lambda)\hat{k}\).

Its projection on \(\hat{c} = \frac{\hat{i} - \hat{j} - \hat{k}}{\sqrt{3}}\) is

\(\frac{(1+\lambda) - (1-\lambda) - (1+\lambda)}{\sqrt{3}} = \frac{\lambda - 1}{\sqrt{3}} = \frac{1}{\sqrt{3}} \Rightarrow \lambda = 2\)

\(\vec{v} = 3\hat{i} - \hat{j} + 3\hat{k}\)

Answer: (A)

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