\( a = i + j + k,\; b = i - j + k\) and c = î -..." - Step-by-step solution, answer key, and detailed explanation on MCA Prep."> \( a = i... - Solved | MCA Prep" /> \( a = i + j + k,\; b = i - j + k\) and c = î -..." - Step-by-step solution, answer key, and detailed explanation on MCA Prep." /> \( a = i... - Solved | MCA Prep" /> \( a = i + j + k,\; b = i - j + k\) and c = î -..." - Step-by-step solution, answer key, and detailed explanation on MCA Prep." />
Let <span class="math-tex">\(\rm \vec a =\hat i +\hat j +\hat k,\; \vec b =\hat i -\hat j + \hat k\)</span> and c = î - ĵ - k̂ be three vectors. A vector <span class="math-tex">\(\rm \vec v\)</span> in the plane of <span class="math-tex">\(\rm \vec a\)</span> and <span class="math-tex">\(\rm \vec b\)</span> whose projection on <span class="math-tex">\(\rm \frac {\vec c} {|\vec c|}\)</span> is <span class="math-tex">\(\frac 1 {\sqrt 3},\)</span> is
A vector in the plane of \(\vec{a}\) and \(\vec{b}\) is \(\vec{v} = \vec{a} + \lambda\vec{b} = (1+\lambda)\hat{i} + (1-\lambda)\hat{j} + (1+\lambda)\hat{k}\).
Its projection on \(\hat{c} = \frac{\hat{i} - \hat{j} - \hat{k}}{\sqrt{3}}\) is
\(\frac{(1+\lambda) - (1-\lambda) - (1+\lambda)}{\sqrt{3}} = \frac{\lambda - 1}{\sqrt{3}} = \frac{1}{\sqrt{3}} \Rightarrow \lambda = 2\)
\(\vec{v} = 3\hat{i} - \hat{j} + 3\hat{k}\)
Answer: (A)
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