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Question 23

Mathematics Scalar and Vector Products Hard

If&nbsp;<span class="math-tex">\(\vec a,\; \vec b\)</span>&nbsp;and&nbsp;<span class="math-tex">\(\vec c\)</span>&nbsp;are the position vectors of the vertices A, B, C of a triangle ABC, then the area of the triangle ABC is

(A) <span class="math-tex">\(\frac 1 2 |\vec a \times \vec b + \vec b \times \vec c + \vec c \times \vec a|\)</span>
(B) <span class="math-tex">\(|\vec a \times \vec b|\)</span>
(C) <span class="math-tex">\(\frac 1 2 |\vec a \times \vec b - \vec b \times \vec c \times -\vec c \times \vec a|\)</span>
(D) <span class="math-tex">\(|\vec a \times (\vec b \times \vec c)|\)</span>
✓ Correct Answer: Option A Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

Area = \(\frac{1}{2}|\vec{AB} \times \vec{AC}| = \frac{1}{2}|(\vec{b} - \vec{a}) \times (\vec{c} - \vec{a})|\)

Expanding: \((\vec{b} - \vec{a}) \times (\vec{c} - \vec{a}) = \vec{b} \times \vec{c} - \vec{b} \times \vec{a} - \vec{a} \times \vec{c} = \vec{a} \times \vec{b} + \vec{b} \times \vec{c} + \vec{c} \times \vec{a}\)

Area = \(\frac{1}{2}|\vec{a} \times \vec{b} + \vec{b} \times \vec{c} + \vec{c} \times \vec{a}|\)

Answer: (A)

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