\( AC =2 i + j + k \) and  \( AC =2 i... - Solved | MCA Prep" /> \( AC =2 i + j + k \) and  \( AC =2 i... - Solved | MCA Prep" /> \( AC =2 i + j + k \) and 

Question 35

Mathematics Scalar and Vector Products Hard

If&nbsp;<span class="math-tex">\(\overrightarrow{AC}=2\hat{i}+\hat{j}+\hat{k}\)</span>&nbsp;and&nbsp;<span class="math-tex">\(\overrightarrow{BD}=-\hat{i}+3\hat{j}+2\hat{k}\)</span>&nbsp;then the area of the quadrilateral ABCD is

(A) <span class="math-tex">\(\dfrac{5}{2}\sqrt{3}\)</span>
(B) <span class="math-tex">\(5\sqrt{3}\)</span>
(C) <span class="math-tex">\(\dfrac{15}{2}\sqrt{3}\)</span>
(D) <span class="math-tex">\(10\sqrt{3}\)</span>
✓ Correct Answer: Option A Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

The area of a quadrilateral with diagonals \(\vec{d_1}\) and \(\vec{d_2}\) is \(\frac{1}{2}|\vec{d_1} \times \vec{d_2}|\).

\(\vec{AC} \times \vec{BD} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \\ 2 & 1 & 1 \\ -1 & 3 & 2 \end{vmatrix} = \hat{i}(2 - 3) - \hat{j}(4 + 1) + \hat{k}(6 + 1) = -\hat{i} - 5\hat{j} + 7\hat{k}\)

Magnitude = \(\sqrt{1 + 25 + 49} = \sqrt{75} = 5\sqrt{3}\)

Area = \(\frac{5\sqrt{3}}{2}\)

Answer: (A)

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