A spherical ball of diameter 21 cm is melted and recast into cubes, each of side 1 cm . The number of cubes thus formed are
Radius = 21/2 = 10.5 cm.
Volume of the sphere = \(\frac{4}{3}\pi r^3 = \frac{4}{3} \times \frac{22}{7} \times 10.5^3 = \frac{4}{3} \times \frac{22}{7} \times 1157.625 = 4851\) cm³
Each cube has volume 1 cm³, so the number of cubes = 4851.
Answer: (A) 4851
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