Question 21

Mathematics Basic Geometry Easy

The locus of a point whose distance from \( (a, 0) \) is equal to its distance from \( y \) -axis, is

(A) \( y^{2}-2 a x+a^{2}=0 \)
(B) \( y-2 a x+a^{2}=0 \)
(C) \( \mathrm{y}^{2}+2 \mathrm{ax}+\mathrm{a}^{2}=0 \)
(D) \( y^{2}-2 a x+a=0 \)
✓ Correct Answer: Option A Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

Let the point be \((x, y)\). Its distance from the y-axis is \(|x|\).

\(\sqrt{(x-a)^2 + y^2} = |x|\)

\(x^2 - 2ax + a^2 + y^2 = x^2 \Rightarrow y^2 - 2ax + a^2 = 0\)

(This is a parabola with focus (a, 0) and the y-axis as its directrix.)

Answer: (A)

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