The acute angle between the lines \( x-2 y+3=0 \) and \( 3 x+y-1=0 \) is
Slopes: \(m_1 = \frac{1}{2}\) (from \(x - 2y + 3 = 0\)) and \(m_2 = -3\) (from \(3x + y - 1 = 0\)).
\(\tan\theta = \left|\frac{m_1 - m_2}{1 + m_1 m_2}\right| = \left|\frac{\frac{1}{2} + 3}{1 - \frac{3}{2}}\right| = \left|\frac{7/2}{-1/2}\right| = 7\)
Acute angle = \(\tan^{-1} 7\)
Answer: (A)
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