NIMCET 2021 Mathematics Question 79 with Solution

Question 79

Mathematics Permutation and Combination Hard

There are 50 questions in a paper. Find the number of ways in which a student can attempt one or more questions :

(A) \({{2}^{50}-1}\)

(B) \({{2}^{50}+1}\)

(C) \({{2}^{50}-2}\)

(D) \({{2}^{50}+2}\)

View Dynamic Solution & Explanation ▼

Correct Solution: Option A

Step-by-step Solution:

Each question can be attempted or not attempted, so there are two choices for each question. Therefore, the total number of ways to attempt the paper is: \[ 2^{50} \] However, this count includes the case when no question is attempted. Excluding this case, the number of ways to attempt the paper is: \[ 2^{50} - 1 \]