Question 79

Mathematics Permutation and Combination Hard

There are 50 questions in a paper. Find the number of ways in which a student can attempt one or more questions :

(A) \({{2}^{50}-1}\)
(B) \({{2}^{50}+1}\)
(C) \({{2}^{50}-2}\)
(D) \({{2}^{50}+2}\)
✓ Correct Answer: Option A Verified Solution

📘 Step-by-Step Solution & Detailed Explanation:

Each question can be attempted or not attempted, so there are two choices for each question. Therefore, the total number of ways to attempt the paper is: \[ 2^{50} \] However, this count includes the case when no question is attempted. Excluding this case, the number of ways to attempt the paper is: \[ 2^{50} - 1 \]

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